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LTE Timing Advance → Distance

Convert an LTE Timing Advance (TA) command into UE–eNodeB distance (and back). Each TA step is 16·Ts ≈ 0.52 µs ≈ 78 m one-way.

📡 LTE Ts = 1/(15000×2048) s · TA step = 16·Ts

The initial TA in the Random Access Response is 11 bits (0–1282), giving up to ~100 km.

How it worksThe TA ↔ distance formula

The eNodeB tells the UE to advance its uplink timing so all UEs' signals arrive aligned. The advance is quantised in steps of 16·Ts, where the LTE basic time unit Ts = 1/(15000×2048) s ≈ 32.55 ns:

step time = 16 × Ts = 16 / (15000 × 2048) ≈ 0.5208 µs

distance (one-way) = TA × (c × 16 × Ts) / 2 ≈ TA × 78.07 m

TA range 0–1282 → 0 – 100.1 km

The factor of ½ is because TA compensates the round trip (UE→eNB→UE), but the cell radius is the one-way distance. In 5G NR the granularity depends on subcarrier spacing (16·64·Tc/2µ), so NR steps are finer than LTE's fixed 78 m — see the SSB tools.

FAQFrequently asked questions

How far is one LTE Timing Advance step?
One TA step (TA = 1) advances timing by 16·Ts ≈ 0.52 µs, which corresponds to about 78 metres of one-way UE–eNodeB distance.
What is the maximum LTE cell range from TA?
The initial TA field is 11 bits (0–1282). At ~78 m per step that gives a maximum of about 100 km, which sets LTE's largest usable cell radius.
What is Ts in LTE?
Ts is the LTE basic time unit, Ts = 1/(15000×2048) s ≈ 32.55 ns — the sample period at the 30.72 MHz reference rate divided down.
Is 5G NR timing advance the same?
No. NR TA uses 16·64·Tc scaled by 2^µ for the subcarrier spacing, so the step (and resolution) changes with numerology and is finer than LTE's fixed 78 m.

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